Optimal. Leaf size=165 \[ -\frac {\sqrt {3} \sqrt [3]{e} q \tan ^{-1}\left (\frac {\sqrt [3]{e}-2 \sqrt [3]{d} (f+g x)}{\sqrt {3} \sqrt [3]{e}}\right )}{\sqrt [3]{d} g}+\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g}+\frac {\sqrt [3]{e} q \log \left (\sqrt [3]{e}+\sqrt [3]{d} (f+g x)\right )}{\sqrt [3]{d} g}-\frac {\sqrt [3]{e} q \log \left (e^{2/3}-\sqrt [3]{d} \sqrt [3]{e} (f+g x)+d^{2/3} (f+g x)^2\right )}{2 \sqrt [3]{d} g} \]
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Rubi [A]
time = 0.11, antiderivative size = 165, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 9, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.562, Rules used = {2533, 2498,
269, 206, 31, 648, 631, 210, 642} \begin {gather*} -\frac {\sqrt {3} \sqrt [3]{e} q \text {ArcTan}\left (\frac {\sqrt [3]{e}-2 \sqrt [3]{d} (f+g x)}{\sqrt {3} \sqrt [3]{e}}\right )}{\sqrt [3]{d} g}+\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g}-\frac {\sqrt [3]{e} q \log \left (d^{2/3} (f+g x)^2-\sqrt [3]{d} \sqrt [3]{e} (f+g x)+e^{2/3}\right )}{2 \sqrt [3]{d} g}+\frac {\sqrt [3]{e} q \log \left (\sqrt [3]{d} (f+g x)+\sqrt [3]{e}\right )}{\sqrt [3]{d} g} \end {gather*}
Antiderivative was successfully verified.
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Rule 31
Rule 206
Rule 210
Rule 269
Rule 631
Rule 642
Rule 648
Rule 2498
Rule 2533
Rubi steps
\begin {align*} \int \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right ) \, dx &=\frac {\text {Subst}\left (\int \log \left (c \left (d+\frac {e}{x^3}\right )^q\right ) \, dx,x,f+g x\right )}{g}\\ &=\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g}+\frac {(3 e q) \text {Subst}\left (\int \frac {1}{\left (d+\frac {e}{x^3}\right ) x^3} \, dx,x,f+g x\right )}{g}\\ &=\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g}+\frac {(3 e q) \text {Subst}\left (\int \frac {1}{e+d x^3} \, dx,x,f+g x\right )}{g}\\ &=\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g}+\frac {\left (\sqrt [3]{e} q\right ) \text {Subst}\left (\int \frac {1}{\sqrt [3]{e}+\sqrt [3]{d} x} \, dx,x,f+g x\right )}{g}+\frac {\left (\sqrt [3]{e} q\right ) \text {Subst}\left (\int \frac {2 \sqrt [3]{e}-\sqrt [3]{d} x}{e^{2/3}-\sqrt [3]{d} \sqrt [3]{e} x+d^{2/3} x^2} \, dx,x,f+g x\right )}{g}\\ &=\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g}+\frac {\sqrt [3]{e} q \log \left (\sqrt [3]{e}+\sqrt [3]{d} (f+g x)\right )}{\sqrt [3]{d} g}-\frac {\left (\sqrt [3]{e} q\right ) \text {Subst}\left (\int \frac {-\sqrt [3]{d} \sqrt [3]{e}+2 d^{2/3} x}{e^{2/3}-\sqrt [3]{d} \sqrt [3]{e} x+d^{2/3} x^2} \, dx,x,f+g x\right )}{2 \sqrt [3]{d} g}+\frac {\left (3 e^{2/3} q\right ) \text {Subst}\left (\int \frac {1}{e^{2/3}-\sqrt [3]{d} \sqrt [3]{e} x+d^{2/3} x^2} \, dx,x,f+g x\right )}{2 g}\\ &=\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g}+\frac {\sqrt [3]{e} q \log \left (\sqrt [3]{e}+\sqrt [3]{d} (f+g x)\right )}{\sqrt [3]{d} g}-\frac {\sqrt [3]{e} q \log \left (e^{2/3}-\sqrt [3]{d} \sqrt [3]{e} (f+g x)+d^{2/3} (f+g x)^2\right )}{2 \sqrt [3]{d} g}+\frac {\left (3 \sqrt [3]{e} q\right ) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\frac {2 \sqrt [3]{d} (f+g x)}{\sqrt [3]{e}}\right )}{\sqrt [3]{d} g}\\ &=-\frac {\sqrt {3} \sqrt [3]{e} q \tan ^{-1}\left (\frac {1-\frac {2 \sqrt [3]{d} (f+g x)}{\sqrt [3]{e}}}{\sqrt {3}}\right )}{\sqrt [3]{d} g}+\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g}+\frac {\sqrt [3]{e} q \log \left (\sqrt [3]{e}+\sqrt [3]{d} (f+g x)\right )}{\sqrt [3]{d} g}-\frac {\sqrt [3]{e} q \log \left (e^{2/3}-\sqrt [3]{d} \sqrt [3]{e} (f+g x)+d^{2/3} (f+g x)^2\right )}{2 \sqrt [3]{d} g}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 3 in
optimal.
time = 0.08, size = 66, normalized size = 0.40 \begin {gather*} -\frac {3 e q \, _2F_1\left (\frac {2}{3},1;\frac {5}{3};-\frac {e}{d (f+g x)^3}\right )}{2 d g (f+g x)^2}+\frac {(f+g x) \log \left (c \left (d+\frac {e}{(f+g x)^3}\right )^q\right )}{g} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
3.
time = 0.06, size = 168, normalized size = 1.02
method | result | size |
default | \(\ln \left (c \left (\frac {d \,g^{3} x^{3}+3 d f \,g^{2} x^{2}+3 d \,f^{2} g x +d \,f^{3}+e}{\left (g x +f \right )^{3}}\right )^{q}\right ) x +3 e g q \left (-\frac {f \ln \left (g x +f \right )}{g^{2} e}+\frac {\munderset {\textit {\_R} =\RootOf \left (d \,g^{3} \textit {\_Z}^{3}+3 d f \,g^{2} \textit {\_Z}^{2}+3 d g \,f^{2} \textit {\_Z} +d \,f^{3}+e \right )}{\sum }\frac {\left (\textit {\_R}^{2} d f \,g^{2}+2 \textit {\_R} d \,f^{2} g +d \,f^{3}+e \right ) \ln \left (x -\textit {\_R} \right )}{g^{2} \textit {\_R}^{2}+2 f g \textit {\_R} +f^{2}}}{3 d \,g^{2} e}\right )\) | \(168\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains complex when optimal does not.
time = 1.11, size = 1424, normalized size = 8.63 \begin {gather*} \frac {4 \, g q x \log \left (\frac {d g^{3} x^{3} + 3 \, d f g^{2} x^{2} + 3 \, d f^{2} g x + d f^{3} + e}{g^{3} x^{3} + 3 \, f g^{2} x^{2} + 3 \, f^{2} g x + f^{3}}\right ) - 4 \, \sqrt {3} g \sqrt {\frac {{\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}^{2} g^{2} + 4 \, {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )} f g q + 4 \, f^{2} q^{2}}{g^{2}}} \arctan \left (-\frac {{\left (2 \, \sqrt {3} \sqrt {4 \, g^{2} q^{2} x^{2} + 12 \, f g q^{2} x + {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}^{2} g^{2} + 12 \, f^{2} q^{2} + 2 \, {\left (g^{2} q x + 3 \, f g q\right )} {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}} {\left ({\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )} d g^{2} + 2 \, d f g q\right )} \sqrt {\frac {{\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}^{2} g^{2} + 4 \, {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )} f g q + 4 \, f^{2} q^{2}}{g^{2}}} - \sqrt {3} {\left (8 \, d f g^{2} q^{2} x + {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}^{2} d g^{3} + 12 \, d f^{2} g q^{2} + 4 \, {\left (d g^{3} q x + 2 \, d f g^{2} q\right )} {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}\right )} \sqrt {\frac {{\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}^{2} g^{2} + 4 \, {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )} f g q + 4 \, f^{2} q^{2}}{g^{2}}}\right )} e^{\left (-1\right )}}{24 \, q^{3}}\right ) - 12 \, f q \log \left (g x + f\right ) - 2 \, {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )} g \log \left (q x - \frac {1}{2} \, {\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} + \frac {f q}{g}\right ) + 4 \, g x \log \left (c\right ) + {\left ({\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )} g + 6 \, f q\right )} \log \left (4 \, g^{2} q^{2} x^{2} + 12 \, f g q^{2} x + {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}^{2} g^{2} + 12 \, f^{2} q^{2} + 2 \, {\left (g^{2} q x + 3 \, f g q\right )} {\left ({\left (-\frac {f^{3} q^{3}}{2 \, g^{3}} + \frac {q^{3} e}{2 \, d g^{3}} + \frac {d f^{3} q^{3} + q^{3} e}{2 \, d g^{3}}\right )}^{\frac {1}{3}} {\left (i \, \sqrt {3} + 1\right )} - \frac {2 \, f q}{g}\right )}\right )}{4 \, g} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 319 vs.
\(2 (125) = 250\).
time = 52.54, size = 319, normalized size = 1.93 \begin {gather*} \frac {1}{2} \, d g^{5} q {\left (\frac {2 \, f e^{\left (-1\right )} \log \left ({\left | d g^{3} x^{3} + 3 \, d f g^{2} x^{2} + 3 \, d f^{2} g x + d f^{3} + e \right |}\right )}{d g^{6}} - \frac {6 \, f e^{\left (-1\right )} \log \left ({\left | g x + f \right |}\right )}{d g^{6}} + \frac {{\left (2 \, \sqrt {3} \left (d^{5} g^{21}\right )^{\frac {1}{3}} \arctan \left (-\frac {d g x + d f + {\left (d^{2}\right )}^{\frac {1}{3}} e^{\frac {1}{3}}}{\sqrt {3} d g x + \sqrt {3} d f - \sqrt {3} {\left (d^{2}\right )}^{\frac {1}{3}} e^{\frac {1}{3}}}\right ) e^{\frac {4}{3}} - \left (d^{5} g^{21}\right )^{\frac {1}{3}} e^{\frac {4}{3}} \log \left (4 \, {\left (\sqrt {3} d g x + \sqrt {3} d f - \sqrt {3} {\left (d^{2}\right )}^{\frac {1}{3}} e^{\frac {1}{3}}\right )}^{2} + 4 \, {\left (d g x + d f + {\left (d^{2}\right )}^{\frac {1}{3}} e^{\frac {1}{3}}\right )}^{2}\right ) + 2 \, \left (d^{5} g^{21}\right )^{\frac {1}{3}} e^{\frac {4}{3}} \log \left ({\left | d g x + d f + {\left (d^{2}\right )}^{\frac {1}{3}} e^{\frac {1}{3}} \right |}\right )\right )} e^{\left (-2\right )}}{d^{3} g^{13}}\right )} e + q x \log \left (d g^{3} x^{3} + 3 \, d f g^{2} x^{2} + 3 \, d f^{2} g x + d f^{3} + e\right ) - q x \log \left (g^{3} x^{3} + 3 \, f g^{2} x^{2} + 3 \, f^{2} g x + f^{3}\right ) + x \log \left (c\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.63, size = 499, normalized size = 3.02 \begin {gather*} x\,\ln \left (c\,{\left (d+\frac {e}{{\left (f+g\,x\right )}^3}\right )}^q\right )-\left (\sum _{k=1}^3\ln \left (-d^2\,e^2\,g^{11}\,\left (3\,e\,q^3\,x+\mathrm {root}\left (d\,g^3\,z^3+3\,d\,f\,g^2\,q\,z^2+3\,d\,f^2\,g\,q^2\,z+d\,f^3\,q^3+e\,q^3,z,k\right )\,e\,q^2+{\mathrm {root}\left (d\,g^3\,z^3+3\,d\,f\,g^2\,q\,z^2+3\,d\,f^2\,g\,q^2\,z+d\,f^3\,q^3+e\,q^3,z,k\right )}^3\,d\,f\,g^2\,4+\mathrm {root}\left (d\,g^3\,z^3+3\,d\,f\,g^2\,q\,z^2+3\,d\,f^2\,g\,q^2\,z+d\,f^3\,q^3+e\,q^3,z,k\right )\,d\,f^3\,q^2\,4+{\mathrm {root}\left (d\,g^3\,z^3+3\,d\,f\,g^2\,q\,z^2+3\,d\,f^2\,g\,q^2\,z+d\,f^3\,q^3+e\,q^3,z,k\right )}^3\,d\,g^3\,x\,4+{\mathrm {root}\left (d\,g^3\,z^3+3\,d\,f\,g^2\,q\,z^2+3\,d\,f^2\,g\,q^2\,z+d\,f^3\,q^3+e\,q^3,z,k\right )}^2\,d\,f^2\,g\,q\,8+\mathrm {root}\left (d\,g^3\,z^3+3\,d\,f\,g^2\,q\,z^2+3\,d\,f^2\,g\,q^2\,z+d\,f^3\,q^3+e\,q^3,z,k\right )\,d\,f^2\,g\,q^2\,x\,4+{\mathrm {root}\left (d\,g^3\,z^3+3\,d\,f\,g^2\,q\,z^2+3\,d\,f^2\,g\,q^2\,z+d\,f^3\,q^3+e\,q^3,z,k\right )}^2\,d\,f\,g^2\,q\,x\,8\right )\,9\right )\,\mathrm {root}\left (d\,g^3\,z^3+3\,d\,f\,g^2\,q\,z^2+3\,d\,f^2\,g\,q^2\,z+d\,f^3\,q^3+e\,q^3,z,k\right )\right )-\frac {3\,f\,q\,\ln \left (f+g\,x\right )}{g} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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